This is suppose to be fast as the previous one was creating a new string
every time u called +=.
On Sun, 2003-01-19 at 23:33, Allan Wick wrote:
> Use a StringBuffer.
>
> StringBuffer theBuffer = StringBuffer();
>
> for (int r = 0; r < selected.length; r++)
> {
> theBuffer.append( rowdata[r] );
> }
>
> String output = theBuffer.toString();
>
> Something like that...
>
> -Al Wick
>
> -----Original Message-----
> From: Roger Lacroix [mailto:[EMAIL PROTECTED]]
> Sent: Sunday, January 19, 2003 5:20 PM
> To: JDJList
> Subject: [jdjlist] Slow: string += string
>
>
> All:
>
> I have my cells of a table defined as Object[][]. In my program, I
> added the ability for the user to select rows of the table to copy to
> the system clipboard (i.e. copy / cut / paste functionality).
>
> Depending on what the user is viewing, there could be 400 rows by 2000
> columns.
> i.e. Object[][] xx = new Object[400][2000];
>
> Say the user selects 20 rows, then I need to combine 40000 cells (20 *
> 2000). I have done every trick that I can think of, but it still is not
> as fast as I would expect. Right now I combine each row into a string
> then I combine each row-string each the final string.
>
> Here is my current code:
>
> String[] rowData = new String[selected.length];
> for (int r = 0; r < selected.length; r++)
> {
> ptr = selected[r];
>
> rowData[r] = msgCells[ptr][1].toString();
> for(int c = 2; c < endColumn; c++)
> {
> if (msgCells[ptr][c] != null)
> {
> rowData[r] += msgCells[ptr][c].toString();
> }
> }
> }
>
> for (int r = 0; r < selected.length; r++)
> {
> tempClipboard += rowData[r];
> }
>
> Does anyone out there in Java land have a tip / trick /snippet of code
> to quickly & efficiently combine a large number of objects into a SINGLE
> string.
>
> Thanks to all.
>
> later
> Roger Lacroix
> Enterprise Architect
> Capitalware Inc.
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--
" In times of profound change, the learners inherit the earth, while the
learned find themselves beautifully equipped to deal with a world that
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