Not sure I understand I now do:
for (int i = 0; i < 4; i++) {
try {
QueueTaskFuture<?> scheduleBuild2 = project.scheduleBuild2(0, new
Cause.UserCause(), myActions[i]);
queue.add(scheduleBuild2);
} catch (Exception e) {
throw new AbortException(e.getMessage());
}
}
for (QueueTaskFuture<?> q : queue) {
q.get();
}
I need to get the results from each job and print some info but it still
does not execute in parallel.
I also found this:
Queue$Item item = Jenkins.getInstance().getQueue().schedule2(null, 0,
myActions[i])
But I still does not give me what I want.
On Sunday, March 9, 2014 10:32:31 PM UTC+1, Daniel Beck wrote:
>
> Don't immediately call .get(), instead assign the Future returned from
> scheduleBuild2 to a variable. Only .get() once you're willing to wait for
> the build to complete.
>
> On 09.03.2014, at 22:27, dev123 <delb...@gmail.com <javascript:>> wrote:
>
> > In a jenkins plugin I am writing I need to run 5 jobs in parallel.
> Currently I do (sequentially):
> >
> > for (int i = 0; i < 4; i++) {
> > try {
> > build = project.scheduleBuild2(0, new Cause.UserCause(),
> myActions[i]).get();
> > } catch (Exception e) {
> > throw new AbortException(e.getMessage());
> > }
> > }
> >
> > How do I trigger these jobs to run in parallel - each one on a separate
> executor?
> >
> >
> > --
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>
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