lihaosky commented on code in PR #14426:
URL: https://github.com/apache/kafka/pull/14426#discussion_r1397782005


##########
streams/src/test/java/org/apache/kafka/streams/kstream/internals/KStreamKStreamLeftJoinTest.java:
##########
@@ -609,17 +842,18 @@ public void testOrdering() {
             inputTopic1.pipeInput(1, "A1", 100L);
             processor.checkAndClearProcessResult();
 
-            // push one item to the other window that has a join; this should 
produce non-joined records with a closed window first, then
-            // the joined records
+            // push one item to the other window that has a join; 
+            // this should produce the joined record first;
+            // then non-joined record with a closed window
             // by the time they were produced before
             // w1 = { 0:A0 (ts: 0), 1:A1 (ts: 100) }
             // w2 = { }
             // --> w1 = { 0:A0 (ts: 0), 1:A1 (ts: 100) }
             // --> w2 = { 1:a1 (ts: 110) }
             inputTopic2.pipeInput(1, "a1", 110L);
             processor.checkAndClearProcessResult(
-                new KeyValueTimestamp<>(0, "A0+null", 0L),
-                new KeyValueTimestamp<>(1, "A1+a1", 110L)
+                new KeyValueTimestamp<>(1, "A1+a1", 110L),
+                new KeyValueTimestamp<>(0, "A0+null", 0L)

Review Comment:
   This is because previously we look at outer store and then join. But this 
change make it we join first and then look at outer store. The ts in outer 
store and other store is hard to reason. If we change the ts of 0 to be 100 and 
ts of 1 to be 50, the original test would still produce 0 first which has 
larger ts... So unless we compare the ts of join and outer at the same time 
when we output, we can't guarantee the order of ts when output.



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