Dear Eric,
This seems to do the trick:
print {*.CA}.sequence.join("")
also
print {*.CA}.group1.join("")
A more verbose version:
t = "";
a = {*.CA};
for ( i=0; i<a.length; i++ ) {
t = t + a[i].group1;
}
print t
I guess they will not be robust enough for all cases, e.g. if there are missing
residues. Some checks could be added to the long version.
------------------------------------------------------------------------------
What NetFlow Analyzer can do for you? Monitors network bandwidth and traffic
patterns at an interface-level. Reveals which users, apps, and protocols are
consuming the most bandwidth. Provides multi-vendor support for NetFlow,
J-Flow, sFlow and other flows. Make informed decisions using capacity planning
reports.http://sdm.link/zohodev2dev
_______________________________________________
Jmol-users mailing list
[email protected]
https://lists.sourceforge.net/lists/listinfo/jmol-users
