How would you deal with the 2036 problem? Years beyond 2036 are giving
date: invalid date `8/31/2088' date: invalid date `4/30/2046' Abdallah On Tue, Jul 15, 2008 at 12:51 PM, Yaman Saqqa <[EMAIL PROTECTED]> wrote: > for d in `cat /tmp/t`; do date +%Y/%m/%d -d $d; done > > On Tue, Jul 15, 2008 at 7:34 PM, Abdallah <[EMAIL PROTECTED]> wrote: >> >> Salam Alaikum Wr Wb >> >> I have a brain teaser of the shell utilities type for you guys. :) >> >> A file foo.txt has a list of date strings in this format: >> >> 8/31/2011 >> 1/7/2020 >> 1/31/2013 >> 11/4/2010 >> >> and so one. >> >> How would one go about flipping them into yyyy/mm/dd format in bar.txt? >> >> as in : >> >> 2011/08/31 >> 2020/01/07 >> 2013/01/31 >> 2010/11/04 >> >> Notice the single digit month or day must become 2 digits. From 8 to 08 >> >> >> "compute regular expressions in his mind at the speed of lighting" Huh! >> >> >> :D >> >> Wasslam Alaikum wr wb >> >> Abdallah >> >> >> ps. The speed of light = 299 792 458 m / s So how many meters do you >> need? >> >> > > > > -- > abulyomon > > www.KiLLTHeUPLiNK.com > > > --~--~---------~--~----~------------~-------~--~----~ ### Jordan Linux Users Group ### http://Jolug.org/ http://groups.google.com/group/Jolug ### Ubuntu Jordan LoCo Team ### https://wiki.ubuntu.com/JordanTeam http://lists.ubuntu.com/ubuntu-jo ### Ojuba Linux ### http://ojuba.org/ ### Jordan PHP ### http://groups.google.com/group/JoPHP -~----------~----~----~----~------~----~------~--~---
