Isn't that parent()? Jörn
On Thu, Jan 15, 2009 at 11:30 AM, Just <[email protected]> wrote: > > Thanks leeoniya ! > > But ":eq(0)" can't work in my case. > Work as ":first" and so return an only one element, so can't get each > parent of each matched element :/. > > I'll look for the closest method. > > But think it should be very interesting to get a "first-ancestor" as > we have a "first-child". > > On 14 jan, 17:21, Leeoniya <[email protected]> wrote: >> you should now be able to use .closest(), although i agree, the naming >> should have been firstancest or something. closest sounds too much >> like a sibling traversal. >> >> i currently constructs like .parents("li:eq(0)") all over the place, >> pretty much identical to Karl's sugg. i think i'll be switching to >> "closest", but be careful, closest can return itself as well if it >> matches, so in a situation like this, they would return the same >> results: >> >> <div> >> <div id="foo"> >> </div> >> </div> >> >> $("#foo").parent("div"); // should return the outer div >> $("#foo").parents("div:eq(0)"); // should return the outer div >> $("#foo").closest("div"); // should return the inner div >> >> Leon >> >> On Jan 14, 9:57 am, Just <[email protected]> wrote: >> >> > No response about that ? Is it so dumby :P ? >> >> > On 16 déc 2008, 16:34, Just <[email protected]> wrote: >> >> > > Hi Ricardo ! >> > > Thanks to answering :). >> >> > > Yea should be "first-ancestor" so. >> >> > > On 16 déc, 13:43, Ricardo Tomasi <[email protected]> wrote: >> >> > > > If you'll allow me, I believe what Just suggested should indeed be >> > > > possible with CSS only, as the same can be achieved in the other >> > > > direction. But the naming is confusing, there is only one possible >> > > > parent so 'first-parent' would be redundant. >> >> > > > Wouldn't that be the case of making the :first pseudo-class match the >> > > > first element for each traversal/element? It's replicating the >> > > > functionality of eq(0) anyway. >> >> > > > Or maybe some 'reverse' selectors: >> > > > $('input.toto < li:first') >> >> > > > On Dec 15, 3:10 pm, Karl Swedberg <[email protected]> wrote: >> >> > > > > You could do this: >> >> > > > > $('input.toto').each(function() { >> > > > > $(this).parents('li:first').remove(); >> >> > > > > }); >> >> > > > > --Karl >> >> > > > > ____________ >> > > > > Karl Swedbergwww.englishrules.comwww.learningjquery.com >> >> > > > > On Dec 15, 2008, at 9:35 AM, Just wrote: >> >> > > > > > Hi John :), >> > > > > > and thanks to answering. >> >> > > > > > Because, as the :first is defined, it just removed the first >> > > > > > element >> > > > > > matched by $('input.toto').parents('li:first'). >> > > > > > Not first LI parent of each element (here each first LI parent of >> > > > > > EACH >> > > > > > input element having the class "toto"). >> >> > > > > > That's my problem so. >> >> > > > > > I thinks that's why first-child exists too. >> >> > > > > > On 12 déc, 18:40, "John Resig" <[email protected]> wrote: >> > > > > >> Why not just do: >> > > > > >> $('input.toto').parents('li:first').remove(); >> >> > > > > >> --John >> >> > > > > >> On Fri, Dec 12, 2008 at 9:54 AM, Just <[email protected]> >> > > > > >> wrote: >> >> > > > > >>> Hi, >> >> > > > > >>> Example : I have list into other list, in few LI element I've got >> > > > > >>> input. I want to take all input element which have the class >> > > > > >>> "toto" >> > > > > >>> and remove the LI which is the parent of the input (not the >> > > > > >>> direct >> > > > > >>> ancestor ;)). >> >> > > > > >>> So it will be good if I could do something like: >> > > > > >>> $('input.toto').parents('li:first-parent').remove(); >> >> > > > > >>> What about that please ? > > > --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "jQuery Development" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/jquery-dev?hl=en -~----------~----~----~----~------~----~------~--~---
