Whoops... spoke to soon. The show method is throwing errors in IE 6. The
main issue is that IE 6 doesn't like setting this[i].style.display to
undefined. Second, it looks like the second for loop is sitting within the
first for loop when I believe the intention was to have them separate, not
nested. Resolved in R6215.
Actually, is that second for loop in show really fixing anything? Typically
we shouldn't need to set the display property again b/c we already set it
once in the first for loop (line 28 of fx.js). The only reason we would set
it again is if the element was still hidden. However, with the second for
loop we are always resetting the display value even if we don't need to.

Looks like we just need to remove the second for loop in show and move the
assignment of style.display back into the if block of the first for loop.
However, I wanted to make sure I wasn't over looking something.

--
Brandon Aaron

On Mon, Feb 16, 2009 at 2:06 PM, Brandon Aaron <[email protected]>wrote:

> No issues here.
> --
> Brandon Aaron
>
>
> On Mon, Feb 16, 2009 at 12:31 PM, John Resig <[email protected]> wrote:
>
>>
>> Hey Everyone -
>>
>> Just finished up the last ticket for 1.3.2 and wanted to throw a copy
>> out for people to try:
>> http://code.jquery.com/nightlies/jquery-2009-02-16.js
>>
>> Please let me know if anything is breaking from 1.3.1 -> 1.3.2.
>>
>> There were some logic changes - specifically with cloning in IE (lots
>> of bug fixes), how the selector engine, how :visible/:hidden work,
>> .height()/.width(), and .ready() in IE - so watch those areas in
>> particular.
>>
>> The current full ticket list can be found here:
>> http://dev.jquery.com/report/33
>>
>> Thanks!
>>
>> --John
>>
>> >>
>>
>

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