I guess the following expression would do: $( $( 'input[value=' + $(this).text() + ']' ) [0] ).remove(); basically you have: - $(YourExpression) that returns the set, - $(YourExpression)[0] that gets the first DOM in your set - $( $(YourExpression)[0] ) that encapsulated said node into a jQuery object on which you can call remove
Unless I'm mistaken. 2009/3/11 Igor <[email protected]> > > try > > $('input[value='+$(this).text()+']').filter(function( i ){ > return i == 0; > }).remove(); > > On 11 мар, 08:48, Bas <[email protected]> wrote: > > if I with the selector $('input[value='+$(this).text()+']') all the > > objects grab they match with the value and count them i got 3 results. > > > > i want to remove the first object in the array from the DOM, i tried > > already some different thins like: > > > > $('input[value='+$(this).text()+']')[0].remove(); > > ($('input[value='+$(this).text()+']')[0]).remove(); > > ($('input[value='+$(this).text()+']'))[0].remove(); > > ($(('input[value='+$(this).text()+']'))[0]).remove(); > > (($('input[value='+$(this).text()+']'))[0]).remove(); > > > > but no result or an error. > > > > who can help me out > > > --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "jQuery Development" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/jquery-dev?hl=en -~----------~----~----~----~------~----~------~--~---
