The problem with your code is that you're re-throwing the event -
which means that debuggers/command-lines will think that the error
originated from the second throw point in the catch, and not the
original location.
Additionally, using setTimeout is no good because the return results
from the functions need to be handled synchronously.
--John
On Wed, Mar 25, 2009 at 12:32 AM, Robert Katić <robert.ka...@gmail.com> wrote:
>
> What about this:
>
> function runHandlers(){
> var h;
> try {
> while ( (h = handlers.shift()) ) {
> h();
> }
> } catch (e) {
> setTimeout(runHandlers);
> throw e;
> }
> }
>
> var handlers = [
> function(){
> throw "A";
> },
> function(){
> throw "B";
> }
> ];
>
> This one will throw both (all) errors.
>
> Am I missing something?
>
> On Mar 24, 10:13 pm, John Resig <jere...@gmail.com> wrote:
>> > I don't think it is the resposibility of the dispatcher to handle
>> > exceptions.
>> > I think it it is the resposibility of the dispatcher to dispatch
>> > events. :-)
>> > An error in one handler should not prevent another handler from
>> > executing.
>> > Nor should a dispatcher suppress errors so that it can complete its
>> > task.
>>
>> Why not just use try/finally, then?
>> Online here, as well:http://ejohn.org/files/handler.html
>>
>> <script>
>> function runHandlers(i){
>> i = i || 0;
>> try {
>> while ( i < handlers.length ) {
>> handlers[i]();
>> i++;
>> }
>> } finally {
>> if ( i < handlers.length ) {
>> runHandlers( i + 1 );
>> }
>> }
>>
>> }
>>
>> var handlers = [
>> function(){
>> document.write("testA<br>");
>> throw "A";
>> },
>> function(){
>> document.write("testB<br>");
>> }
>> ];
>>
>> try {
>> runHandlers();} catch(e){
>>
>> document.write("ERROR: " + e + "<br>");}
>>
>> </script>
>>
>> Output:
>> testA
>> testB
>> ERROR: A
>>
>> I don't think the order of the error is terribly important in this
>> case. At the very least, though, you get the best of all worlds: All
>> handlers execute, exceptions are thrown, and performance isn't
>> sacrificed.
>>
>> --John
> >
>
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