Thank you for all the help and suggestions guys.
Nice idea about the caching Brandon, I'll certainly look into that.
John you solution is elegant as always, that was exactly what I was
looking for.
Thanks again everyone.
Marcus
On 30 Mar, 22:32, John Resig <jere...@gmail.com> wrote:
> If I'm understanding the problem correctly, you'll want this:
>
> $(".gallery img").clone().appendTo("#bild_spel div ul").wrap("<li></li>");
>
> (remove the .clone() if you want to move the img elements, as well)
>
> --John
>
> On Mon, Mar 30, 2009 at 6:48 AM, smurkas <marcus.dalg...@gmail.com> wrote:
>
> > Hello.
>
> > I have a situation where I have grabbed a couple of images off a page
> > and want to insert them again into an unordered list. Grabbing the
> > images was no problem but I don't know what to write when inserting
> > them again.
> > The code below does not result in the images being inserted again,
> > instead each list item contains
> > [object HTMLImageElement] as text. I also tried wrapping this in $
> > (this) but that didn't work either. The solution is probably dead
> > simple but right now I am missing it. Can anyone help me out?
>
> > var img = $(".gallery img");
> > $(img).each(function() {
> > $("#bild_spel div ul").append('<li>'+this+'</li>');
> > });
>
> > Kindly, Marcus.
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