you still haven't clarified what you're trying to do. Are you trying
to get the mouse position or the offset coordinates of the moused over
element?
And where are you calling the showMenu function?
--Karl
On Jul 27, 2009, at 3:37 PM, GONNY wrote:
>
>
> function showMenu(e)
> {
> document.onmouseup = hideMenu;
> var mailMenu = EBID('mailMenu');
> /*
> var offset = e.offset();
> or
> var offset = mailMenu.offset();
> */
> mailMenu.style.left = offset.left + 'px';
> mailMenu.style.top = offset.top + 'px';
> mailMenu.style.display = '';
> }
> not work :(
>
> can give me an example how can do it.
>
> On 27 Lug, 15:36, Karl Swedberg <k...@englishrules.com> wrote:
>> On Jul 27, 2009, at 8:20 AM, GONNY wrote:
>>
>>> e.clientY and eclientx not work properly.
>>
>> Your subject refers to offset left/top, but it looks like your
>> function is trying to get the mouse coordinates (e.clientX/e.clientY)
>>
>> for offset, use jQuery's offset method:
>>
>> http://docs.jquery.com/CSS/offset
>>
>> for mouse coordinates, use e.pageX and e.pageY:
>>
>> http://docs.jquery.com/Events/jQuery.Event#event.pageX.2FY
>>
>> This article may help explain why e.clientX/e.clientY aren't working
>> for you:
>>
>> http://www.quirksmode.org/js/events_properties.html#position
>>
>> "As to the mouse position, the situation is horrible. Although there
>> are no less than six mouse coordinates property pairs, there is no
>> reliable cross–browser way to find the mouse coordinates relative to
>> the document we need."
>>
>> --Karl
>>
>> ____________
>> Karl Swedbergwww.englishrules.comwww.learningjquery.com
> >
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