This might be even more robust solution :
$C.fadeOut(
verbTime,
(function( str, fade_time ){
return function(){ $THAT.text( str ).fadeIn
( fade_time ); }
})( ARR[i], verbTime )
);
-- DBJ
On Aug 12, 9:15 am, Andrea Giammarchi <[email protected]>
wrote:
> Come on Dave don't be that precious :D
>
> $C.fadeOut(
> verbTime,
> (function(str){
> return function(){$THAT.text(str).fadeIn(verbTime);}
> })(ARR[i])
> );
>
> On Wed, Aug 12, 2009 at 1:54 AM, Dave Methvin <[email protected]>wrote:
>
>
>
> > > for(var i = 0; i<ARR.length; i++){
> > > $C.fadeOut(
> > > verbTime,
> > > function(){$THAT.text(ARR[i]).fadeIn(verbTime);}
> > > );
> > > }
> > > }
>
> > That code has the same problem as the original, though. It is going to
> > queue up ARR.length-1 fadeOut operations that all have i==ARR.length
> > and fail. To get the code to work you need to create a closure
> > *within* the loop that captures the current loop value, which
> > jQuery.each does for you. Or am I missing something?
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