i guess i just found a bug? At line 3961, the filter variable is not declared properly. After adding back a "var" at the beginning, the error in my app is gone.
(Strangely, at the same line no semicolon at the end?) On Dec 5, 4:44 am, John Resig <jere...@gmail.com> wrote: > More details > here:http://blog.jquery.com/2009/12/04/jquery-14-alpha-1-released/ > > --John -- You received this message because you are subscribed to the Google Groups "jQuery Development" group. To post to this group, send email to jquery-...@googlegroups.com. To unsubscribe from this group, send email to jquery-dev+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/jquery-dev?hl=en.
