Right. but i need all the "first" paragraph of each "page", to execute an
"each" function for each one :)
Ok. this is what i looking, put in cap each letter of only the first
paragraph of each sign, like a combination of fancy drop caps part 1 and
fancy drop caps part 2
http://www.learningjquery.com/2006/10/fancy-drop-cap-part-1
http://www.learningjquery.com/2006/10/fancy-drop-cap-part-2
$(document).ready(function(){
swap_letter();
});
function swap_letter() {
var parag = $('.firma p:first'); <----- Only get the fisrt
parag.each(function(index) {
var first_paragraph = this;
if (!first_paragraph) return false;
var node = first_paragraph;
while (node.childNodes.length) {
node = node.firstChild;
}
var text = node.nodeValue;
var first_letter = text.substr(0,1);
var match = /[a-zA-Z]/.test(first_letter);
if ( match ) {
node.nodeValue = text.slice(1);
$('<img />')
.attr('src','assets/alphabet/' + first_letter.toLowerCase() + '.gif')
.attr('alt',first_letter)
.addClass('fancy-letter')
.prependTo( first_paragraph );
}
});
}
----- Original Message -----
From: "Joel Birch" <[EMAIL PROTECTED]>
To: <jquery-en@googlegroups.com>
Sent: Tuesday, June 05, 2007 11:40 AM
Subject: [jQuery] Re: Problem getting first paragraph
How about:
var first_paragraphs = $('#book div.page p:first');
Joel.
On 06/06/2007, at 12:34 AM, Sebastián V. Würtz wrote:
How i get the first p of each div page inside the id book?
This not work
$('#book .page').each(function(index) {
var first_paragraph = $(this + " p").eq(0);
<div id="book">
<div class="page">
<h1>xxxxxxx</h1>
<p>cccccccc</p>
<p>dddddd</p>
</div>
<div class="page">
<h1>asdasdas</h1>
<p>cccccccc</p>
<p>tttttttt</p>
</div>
<div class="page">
<h1>2222222</h1>
<p>cccccccc</p>
</div>
</div>
thx
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