[jQuery] Re: Append "Area" to Map

[Jimmy Glass]

Absolutely! 

Before:
<DIV ID="MapContainer">

    <MAP id="thisMap" NAME="thisMap2">

    </MAP>

</DIV>

<img src="http://sf-ips-01/is/image/DWR/IS_10147"; id="s7Image" 
USEMAP="thisMap2" />

After: ( I get the Areas as a string)
<DIV ID="MapContainer">
    <MAP id="thisMap" NAME="thisMap2">
        <area href="javascript:alert(&#39;10147&#39;);" tenabledthis="true" 
template="javascript:alert(&#39;10147&#39;);return false;" 
templateenabled="false" alt="10147 &#45; Chair" shape="poly" 
coords="192,154,192,352,390,352,390,154">
        <area href="javascript:alert(&#39;10148&#39;);" tenabledthis="true" 
template="javascript:alert(&#39;10147&#39;);return false;" 
templateenabled="false" alt="10147 &#45; Ottoman" shape="poly" 
coords="0,187,0,386,198,386,198,187">
    </MAP>
</DIV>
<img src="http://sf-ips-01/is/image/DWR/IS_10147"; id="s7Image" 
USEMAP="thisMap2" />

----------------------------------------
From: "Matt Stith" <[EMAIL PROTECTED]>
Sent: Friday, June 08, 2007 4:11 PM
To: jquery-en@googlegroups.com
Subject: [jQuery] Re: Append "Area" to Map 

A bit of HTML would help a bit!

On 6/8/07, Jimmy Glass <[EMAIL PROTECTED]> wrote:
I have been trying to append a freaking Area tag to a MAP tag for about 2 hours 
now... 

The data argument is always a string.

function(data)
                                                {   
                                                    
$('#s7Image').attr('usemap','');

                                                   $('#MapContainer').empty();
                                                    thisMap = '<MAP 
ID="thisMap2" NAME="thisMap2"></MAP>';

                                                    
$('#MapContainer').append(thisMap);
                                                    
                                                   $('#thisMap').append(data);

                                                    
                                                    
$('#s7Image').attr('usemap','thisMap2');
                                                }

Is there something obvious that I'm missing here? Any thoughts would be greatly 
appreciated.

Jimmy G