json_encode should also produce valid JSON, which this isn't:
{ok:true,state:'OUT-DECOMMISSIONED'}
That is a valid JavaScript object literal, so it will work in most cases when
the "JSON" code is being loaded by JavaScript, but if you ever need to feed
JSON into a strict JSON parser it won't work.
Valid JSON for this would be:
{"ok":true,"state":"OUT-DECOMMISSIONED"}
IOW, all labels must be quoted, and all quotes are double quotes, not single
quotes. See http://json.org/ for the full syntax.
-Mike
_____
From: ????
Jake,
json_encode is very cool, and it looks like it would take care of everyone's
problems...
THANKS!
On 6/18/07, Jake McGraw < [EMAIL PROTECTED] <mailto:[EMAIL PROTECTED]> > wrote:
I think Jake nailed it, when using php and json, why not use
json_encode? Observe:
echo json_encode(array("ok"=>true,"state"=>"OUT-DECOMMISSIONED"));
php-json is native in PHP 5.2 and above, and available as a plugin here:
http://aurore.net/projects/php-json/
and will always* produce valid json from arrays.
- jake
* - As much as I've used it, I haven't come across a single problem.
On 6/18/07, Ⓙⓐⓚⓔ <[EMAIL PROTECTED]> wrote:
> do you have variables named OUT and DECOMMISSIONED?
>
> or did you mean 'OUT-DECOMMISSIONED'
>
> as in
>
> <?
> echo "{ok:true,state:'OUT-DECOMMISSIONED'}";
> > ?>
>
>
>
> On 6/18/07, Brad Perkins < [EMAIL PROTECTED] <mailto:[EMAIL PROTECTED]> >
> wrote:
> >
> > I'm trying to use getJSON to return some JSON from a PHP page. I can
> > see that the request is returning the expected response with Firebug,
> > but the getJSON callback isn't firing?
> >
> > My PHP is simply
> >
> > <?
> > echo "{ok:true,state:OUT-DECOMMISSIONED}";
> > ?>
> >
> > Do a need to set a special content type before returning the JSON?
> >
> >
>
>
>
> --
> Ⓙⓐⓚⓔ - יעקב ʝǡǩȩ ᎫᎪᏦᎬ
--
Ⓙⓐⓚⓔ - יעקב ʝǡǩȩ ᎫᎪᏦᎬ
