Thank you for the reply mike,
Unfortunately I don't understand how I could use this? What is the
formatted column? I think i understand that you would be running this
code $('#comments h1') after the (data) for the form is complete.
On Jul 13, 4:17 am, "Mike Alsup" <[EMAIL PROTECTED]> wrote:
> Chris,
>
> Why don't you return the formatted column when it is posted. Then you
> could do something like this:
>
> $(document).ready(function() {
> $('#myForm').ajaxForm(function(data) {
> $('#thankyou').show('slow');
> $('newcomment').hide();
> $('#comments h1').after(data);
> });
>
> });
>
> Mike
>
> On 7/13/07, Chris <[EMAIL PROTECTED]> wrote:
>
>
>
> > Hello everyone,
> > I'm a bit of a noob to this whole AJAX thing so you'll have to forgive
> > me. I've setup a blog, using jQuery the comments are added to mysql
> > using this form plugin (http://www.malsup.com/jquery/form/#getting-
> > started). Posting the comments work great, I was even able to add in
> > a confirmation saying "Thank you for posting". My dilemma is showing
> > the new comment on the page without refreshing. Here is the page to
> > test it: (http://www.iphoneappr.com/index.php?post=48). I was
> > thinking I could do a $.get to an external php page that queries
> > mysql with the most current post and put it in a specific div on the
> > page.
> > Here is the function for the form.
>
> > <script type="text/javascript">
> > // wait for the DOM to be loaded
> > $(document).ready(function() {
> > // bind 'myForm' and provide a simple callback function
> > $('#myForm').ajaxForm(function() {
> > $('#thankyou').show('slow');
> > $('#newcomment').hide('fast');
>
> > });
> > });
>
> > </script>
>
> > Thank you for any help! This is driving me nuts!!!!!
