Angelo,
That would be how I would do it and all you need to add to the list depends
on a few things:
You may want to do something like:
//inside you ajax
if(THERE IS NEW IMAGE){
var td = $('<td>').appendTo('table'); // or prependTo('table');
// maybe append a notice that a new image is loading
var newsrc = imageUrl;
var newimage = new Image();
newimage.onload = function(){
td.empty().append(this);
}
newimage.src = newsrc;
}
Of course that is not tested, but I did something similar in another
project.
On 9/6/07, Angelo Zanetti <[EMAIL PROTECTED]> wrote:
>
>
> Hi all
>
> This is more of a general question but is linked to JQuery.
>
> Here is the scenario:
>
> I have an image gallery and while users are viewing the gallery a new
> image is added. I want to be able to dynamically show the new image to
> the user if they are on the last page.
> So basically my thoughts on how it will work are as follows:
>
> every few seconds an XMLHttpRequest will be made to the server to check
> if there are any new images (that functionality doesnt need to be
> discussed here).
> If there is a new image the response will indicate that.
>
> Now how would I show the image in the gallery? Say its a table and there
> is an open <td> for example? Im sure I can place a <div> in the <td> and
> an <img> in the div and populate that with the src but Im not sure if
> the image will display?
>
> Is there something wrong with my logic? or is there another way to do
> this?
>
> I have been going through:
>
> http://ajaxpatterns.org/Periodic_Refresh
>
> I'd appreciate any comments and help.
>
> Thanks in advance.
> --
> ------------------------------------------------------------------------
> Angelo Zanetti
> Systems developer
> ------------------------------------------------------------------------
>
> *Telephone:* +27 (021) 552 9799
> *Mobile:* +27 (0) 72 441 3355
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> *
> Web:* http://www.zlogic.co.za
> *E-Mail:* [EMAIL PROTECTED] <mailto:[EMAIL PROTECTED]>
>
>
>
--
Benjamin Sterling
http://www.KenzoMedia.com
http://www.KenzoHosting.com
