Even with the XPath plugin, you won't be able to use that selector.
jQuery always only supported a subset of XPath, not the full spec.
The "div[2]" part, for example, won't be recognized correctly by
jQuery, in any version.
--Karl
_________________
Karl Swedberg
www.englishrules.com
www.learningjquery.com
On Sep 16, 2007, at 6:12 PM, Erik Beeson wrote:
If you're using jQuery 1.2, you need the XPath plugin, available here:
http://docs.jquery.com/Release:jQuery_1.2#XPath_Compatibility_Plugin
See here for more info:
http://docs.jquery.com/Release:jQuery_1.2#Removed_Functionality
--Erik
On 9/16/07, [EMAIL PROTECTED] <[EMAIL PROTECTED]> wrote:
I went through John Resigs screencast on using jquery with firebug at
http://jquery.com/blog/2007/01/26/introduction-to-firebug-and-
jquery-screencast/
I tried using xpath in the firebug console but get no results for a
xpath that I get from firebug when inspecting a text element
alert($("/html/body/div/div[2]/div[4]/div[4]/div/div/div[2]/div/
p",document).text());
also tried
alert($("/html/body/div/div[2]/div[4]/div[4]/div/div/div[2]/div/
p").text());
Get a blank alert.
Also tried adding it to the the html page to make sure it was not
working from there.
Whats wrong with the XPATH? I copied the xpath using firebugs "Copy
XPATH".
Is this a known issue? Is there a workaround?
Does anyone have a html page with working XPATH examples. I think this
would really help newbies.
Thanks
-Milind
