I think I am starting to get lost...
The links are supposed to be triggering the jQuery function...
what class or id do they use?
<div class="MenuContent" style="background: #FFF; height: 210px;">
<p class="centered" style="height: 80px;">
<img id="imgLinkAct" src="images/NCQ8_swap.jpg" width="97"
height="75"/>
<img id="imgLinkAct" src="images/NCQ8_swap.jpg" rel="images/
cylinder.jpg" class="swapImages"/>
<img id="imgLinkAct" src="images/NCQ8_swap.jpg" rel="images/
mgp_swap.jpg" class="swapImages"/>
<img id="imgLinkAct" src="images/NCQ8_swap.jpg" rel="images/
mhc_swap.jpg" class="swapImages"/>
<img id="imgLinkAct" src="images/NCQ8_swap.jpg" rel="images/
shock_swap.jpg" class="swapImages"/>
<img id="imgLinkAct" src="images/NCQ8_swap.jpg" rel="images/
emy2_swap.jpg" class="swapImages"/>
<img id="imgLinkAct" src="images/NCQ8_swap.jpg" rel="images/
ncy2_swap.jpg" class="swapImages"/>
<img id="imgLinkAct" src="images/NCQ8_swap.jpg" rel="images/
crq_swap.jpg" class="swapImages"/>
<img id="imgLinkAct" src="images/NCQ8_swap.jpg" rel="images/
clean_room_swap.jpg" class="swapImages"/>
</p>
<p style="margin-left: 2%;">
<a href="linear_actuators.html" class="showPic">Linear Actuators</
a><br/>
<a href="#" class="showPic2">Guided Actuators</a><br/>
<a href="#" class="showPic3">Grippers & Escapements</a><br/>
<a href="#" class="showPic4">Actuator Accessories</a><br/>
<a href="#" class="showPic5">Electric Actuators</a><br/>
<a href="#" class="showPic6">Rodless Actuators</a><br/>
<a href="#" class="showPic7">Rotary Actuators</a><br/>
<a href="#" class="showPic8">Specialty Actuators</a><br/></p>
</div>
On Sep 26, 9:34 am, Karl Swedberg <[EMAIL PROTECTED]> wrote:
> The problem here is that .hover() takes two arguments, one for
> mouseover and one for mouseout.
>
> So it should look like this:
>
> .hover(function() {
> // Stuff to do when the mouse enters the element;}, function() {
>
> // Stuff to do when the mouse leaves the element;
>
> });
>
> If you just want to do something on mouseover, use the (appropriately
> named) .mouseover() method instead:
>
> .mouseover(function() {
> // Stuff to do when the mouse enters the element
>
> })
>
> --Karl
> _________________
> Karl Swedbergwww.englishrules.comwww.learningjquery.com
>
> On Sep 26, 2007, at 9:17 AM, Danjojo wrote:
>
>
>
>
>
> > I am doing a simple imageChange onLinkHover...
>
> > I get the following error in Firebug everytime I hover over a link.
> > But the image swaps work GREAT in all browsers.
> > Except for the fact I see the error getting thrown in the browsers I
> > am fine.
>
> > g has no properties
> > handleHover(Object type=mouseout target=a.showPic)jquery-svn.js (line
> > 11)
> > e(Object type=mouseout target=a.showPic)jquery-svn.js (line 11)
> > e()jquery-svn.js (line 11)
> > [Break on this error] eval(function(p,a,c,k,e,r){e=function(c)
> > {return(c<a?'':e(parseInt(c/a)))+((c=c%a...
>
> > The jQuery code to swap images is:
>
> > $(".showPic").hover(function() {
> > $("#imgLinkAct").attr("src", "images/cylinder.jpg");
> > });
> > $(".showPic2").hover(function() {
> > $("#imgLinkAct").attr("src", "images/mgp_swap.jpg");
> > });
> > $(".showPic3").hover(function() {
> > $("#imgLinkAct").attr("src", "images/mhc_swap.jpg");
> > });
> > $(".showPic4").hover(function() {
> > $("#imgLinkAct").attr("src", "images/shock_swap.jpg");
> > });
> > $(".showPic5").hover(function() {
> > $("#imgLinkAct").attr("src", "images/emy2_swap.jpg");
> > });
> > $(".showPic6").hover(function() {
> > $("#imgLinkAct").attr("src", "images/ncy2_swap.jpg");
> > });
> > $(".showPic7").hover(function() {
> > $("#imgLinkAct").attr("src", "images/crq_swap.jpg");
> > });
> > $(".showPic8").hover(function() {
> > $("#imgLinkAct").attr("src", "images/clean_room_swap.jpg");
> > });
>
> > });- Hide quoted text -
>
> - Show quoted text -
