Thanks, this works, I notice that css("display") will return "block"
when there is no "style" defined
On Oct 28, 7:13 pm, James Dempster <[EMAIL PROTECTED]> wrote:
> Try $('label').css('display'); this will return the value your looking
> for.
>
> On Oct 28, 7:39 am, "[EMAIL PROTECTED]"
>
> <[EMAIL PROTECTED]> wrote:
> > Hi,
>
> > Given following, is there a way to get the value of 'display'? is it
> > 'none' or something else?
> > thanks,
>
> > AC.
>
> > <label for="state" style="display:none;">
