Thanks Karl.
Unfortunately I can't guarantee there will be one (or more) tables at
all. I'm using dynamic content, so some rows may have one or more sub
tables, while others will have none...
I *might* be able to rework the code some so there are no nested tables
(use DIVs instead to get a row effect...). That would solve my issue
too.. :)
For now, using the context seems to be working.
Shawn
Karl Swedberg wrote:
>
> Hi Shawn,
>
>
> On Jan 2, 2008, at 5:30 AM, Shawn wrote:
>> I'm working on a table that has nested tables. My problem is that I
>> need to retrieve all the rows for the main table, but ignore the nested
>> tables. I know I can do something like this:
>>
>> $("#mytable > tbody > tr");
>>
>>
>> But my table reference is passed into my function(s) as a parameter. So
>> can I do something like this then?
>>
>> $("tbody > tr", tblRef);
>
> No. That won't work, as you suggest below.
>
>> If I'm understanding correctly that would give me all the TRs within the
>> context of my tblRef element. But wouldn't that also include the nested
>> tables? Or maybe this
>>
>> $("tbody:first > tr", tblRef);
>>
>> ??
>
> yes, that should work.
>
>> I know as a fallback I can do
>> $(tblRef).children("tbody").children("tr"); But that seems inefficient
>> to me...
>>
>> Any tips on doing this? Thanks in advance.
>
> Your solution works for me:
>
> $("tbody:first > tr", tblRef);
>
> Another option would be this:
>
> $("> tbody > tr", tblRef);
>
> If you're sure there will be one nested table, and you want to select
> the <tr> only in the outer table, you could also do this:
>
> $('tr:has(table)', tblRef);
>
> Cheers,
>
> --Karl
> _________________
> Karl Swedberg
> www.englishrules.com
> www.learningjquery.com
>
