[jQuery] Re: Appending content in order

[Feijó]

Hi Karl, Its a bit more confunsing, I simplified too much In my div, I change a value from a <select> that triggers a code that clone the <select> parent (the div) If I do that a few times, every new div goes to the bottom I do not know what eq() is!! there is a function that return that? Here is a sample of current code:     $("#thefilter img#new-criteria").click(function(){         $last = $('#thefilter .qz-tablefield:eq(1)')             .clone(true);         $last             .appendTo($('#qz-criteria'))             .hide()             .fadeIn('medium')             .find('.clean-criteria')             .trigger('click');     }); my <select> triggers that event.  How to adjust with your suggestion? Feijó Karl Swedberg escreveu: Hi Feijó, you could try this ... $('div.main > div.sub:eq(2)').after('<div class="sub"></div>'); That should insert your new div after the 3rd one. --Karl _________________ Karl Swedberg www.englishrules.com www.learningjquery.com On Feb 11, 2008, at 2:25 PM, Feijó wrote: consider that html: <div class=main>     <div class=sub></div>     <div class=sub></div>     <div class=sub></div>     <div class=sub></div>     <div class=sub></div> </div> I need to append a new <div class=sub></div> as the 2nd, 3rd, middle, etc. Append() add after the last one. How can I do that? Its possible? Thanks Feijó