if you load the minified or packed version of jquery, and have gzip compression on your server (which everyone should have anyways), jquery is only around 15kb! is that heavy?
On Mar 5, 10:51 am, Jonny <[EMAIL PROTECTED]> wrote: > Ok, sorry, never mind, I guess there was just a delay in this post > going live, sorry for my impatience :/ > > Just to clarify, this is not really a Jquery question, but this group > seems to be the most active one that has AJAX experts in it, so that's > why I posted it here. I know that the people who are asking this > question (through me) are not wanting to load a heavy js library > (Jquery), so the advice below won't really work :( > > - J > > On Mar 4, 2:54 pm, "Jonny M" <[EMAIL PROTECTED]> wrote: > > > I posted this almost an hour ago and it is still not showing up in the > > Google Group... why? > > > - Jonny > > > On Tue, Mar 4, 2008 at 2:01 PM, Jonny <[EMAIL PROTECTED]> wrote: > > > Basically, I have a JavaScript function (let's call the function > > > "displayDiv") that ends up writing a <div> to the page. If > > > "displayDiv" is called within a table cell, the <div> will be added > > > and displayed in that table cell. Now, what I'm trying to accomplish > > > is replicating this behaviour with an AJAX function (let's call the > > > function "callAJAX") that returns HTML containing "displayDiv" and > > > adding the code to a specific location in the page. I have tried > > > this, problem is that the JavaScript returned from "callAJAX" was not > > > executed. > > > > I then did some research and tried a few things: > > > > 1. I tried parsing out the JavaScript (displayDiv) from the > > > returned HTML (callAJAX) and adding it to the <head> tag, which in > > > theory, should be executed. This approach did not work for me because > > > "displayDiv" writes a <div> to the page and from the <head> it would > > > not know where to write the <div>. > > > > 2. I have tried parsing out the JavaScript (displayDiv) from the > > > returned HTML (callAJAX) and executing it with EVAL() but this would > > > not work because the AJAX function would not know where to write the > > > <div> created within the "displayDiv" function. > > > > I guess what I'm hoping for is some magical piece of code that would > > > tell the browser to parse the page again and execute the JavaScript > > > that was added to the page by the AJAX function. > > > > ============================ > > > > I am posting this on behalf of a friend who is to busy today :) If > > > anyone can tell me if this is even possible, and if so, where to go > > > next, that would be most excellent! > > > > Many thanks, > > > > - Jonny
