$(".closeimage_left").click( function () {
  $(this).siblings(".boxcontent").hide();
});

That *should* do the trick.

Shawn

thekman wrote:
Hi all,
I have code something like:

<div id="box_1" class=box>
  <div id="close_1_a" class="closeimage_left"></div>
  <div id="title_1" class="boxtitle">Box Title</div>
  <div id="close_1_b" class="closeimage_right">Box Title</div>
  <div id="content_1" class="boxcontent">box content...</div>
</div>
<div id="box_2" class=box>
  <div id="close_2_a" class="closeimage_left"></div>
  <div id="title_2" class="boxtitle">Box Title</div>
  <div id="close_2_b" class="closeimage_right">Box Title</div>
  <div id="content_2" class="boxcontent">box content...</div>
</div>

All numbers are dynamically generated from the database.

What is the best way to use jquery to close the correct content div?
I am presuming I would use something like below, but what do I put in
the click function?

$(".closeimage_left").click(function() {
   });

Reply via email to