I suppose it just depends whether it's faster to find and hide all then filter some or all and show them, or to selectively hide/show each of a known set? Haven't tested so not sure.
On May 10, 4:22 am, Dave Methvin <[EMAIL PROTECTED]> wrote: > How about this? > > $('#hotel_paese').change(function(){ > $('#hotel_destinazione option').hide() > .filter(this.value? ("."+this.value) : "*").show(); > > }); > > I think I got that right...if not you can probably tell what I meant.