jQuery UI depends on jQuery 1.2.4a because we are making new updates to jQuery to make sure jQuery UI performs its best. The final version of jQuery UI will also have a final version of jQuery to go along with it.
-- Brandon Aaron On May 11, 8:59 pm, Eric Ongerth <[EMAIL PROTECTED]> wrote: > Oh, ok. Thank you. The jQuery website gave me no idea that jquery ui > 1.5b4 was dependent on jquery 1.2.4a. In fact I had no idea 1.2.4a > was even available. > > Allright... I switched to the (nightly) 1.2.4a, and the error of > course disappeared. > > The jqueryUI site could make it more clear that a specific jquery > build is required. Also, isn't it a little strange that a beta build > depends on an alpha in this case? (1.5b4 depending on 1.2.4a) ? > > What would I downgrade to if I wanted to run stable versions of both > jquery and jquery-ui? > > Thanks! > Eric > > On May 11, 6:38 pm, Ariel Flesler <[EMAIL PROTECTED]> wrote: > > > OuterWidth has been include along with the rest of Dimensions' methods > > into jQuery 1.2.4a which (as far as I know) is the release that comes > > with the last UI. > > > Are you seeing this on Safari ? I got a failing test on Safari for > > outerWidth. > > > -- > > Ariel Fleslerhttp://flesler.blogspot.com > > > On 11 mayo, 21:59, Eric Ongerth <[EMAIL PROTECTED]> wrote: > > > > Take a look the following from jquery.ui-all-1.5b4.js: -- it's inside > > > of the droppable() method's init method: > > > > 802 //Store the droppable's proportions > > > 803 this.proportions = { width: this.element.outerWidth(), height: > > > this.element.outerHeight() }; > > > > I have been stuck for a while on an error this causes. I am calling > > > droppable() on a div and I get an error saying this.element.outerWidth > > > is not a function. Of course, because elements don't have an > > > outerWidth! The div from which I'm calling droppable() has a width, > > > offsetWidth(), scrollWidth(), as checked with a Firebug breakpoint at > > > the time of calling droppable(). But it naturally does not have an > > > outerWidth(). > > > > This seems like an error in jquery-ui. But if that were true, > > > wouldn't people have tripped over it everywhere? Therefore it makes > > > me wonder what I am doing wrong instead. > > > > Can anyone offer some insight about this? > > > > Eric
