I'm not sure what you mean by "uppermost," but you can select the
wrapper div closest to the span with $
('span.bullet').parents('div.wrapper:first') or furthest out from the
span with $('span.bullet').parents('div.wrapper:last')
--Karl
_________________
Karl Swedberg
www.englishrules.com
www.learningjquery.com
On May 22, 2008, at 4:54 PM, EdMartin wrote:
I have a setup like this
<div id="container">
<div class="wrapper">
<div class="wrapper">
<div><span class="bullet">Bullet</span>
<!-- other stuff, potentially inner divs also containing bullets --
</div>
</div>
</div>
</div>
where there is an unknown number of wrapping "wrapper" divs. I want to
select the uppermost divs that contain a span.bullet, regardless of
the amount of wrapping. All such uppermost span.bullet-containg divs
will be wrapped to the same depth. But any or all of them may contain
other span.bullet-containing divs -- I don't want to select such non-
uppermost divs.
In practice, the depth of wrapping is probably only 0, 1, 2, or 3. So
I could deal with each of those separately, like this:
$( '#container' ).children().filter( ':has( span.bullet )' ) // no
wrapping
$
( '#container
' ).children
().filter( '.wrapper' ).children().filter( ':has( span.bullet )' ) //
1 layer of wrapping
and so on. But surely there has to be a more elegant way.
Any suggestions?
