And in case you want to shorten the parseInt:
var n = +"forum-list-1".split('-').pop();
--Klaus
On 15 Jun., 14:24, Klaus Hartl <[EMAIL PROTECTED]> wrote:
> var n = parseInt(/\d/.exec("forum-list-1")[0]);
>
> Or even easier using split (if you can rely on the format of the
> string) - pretty much what Ariel already showed:
>
> var n = parseInt("forum-list-1".split('-').pop());
>
> --Klaus
>
> On 15 Jun., 13:18, yo2lux <[EMAIL PROTECTED]> wrote:
>
> > Thanks and which is the best way to obtain the last number of string,
> > for example I have:
>
> > forum-list-1
> > forum-list-2
> > forum-list-3
>
> > I need the numbers: 1, 2 or 3.
>
> > On Jun 12, 6:44 pm, Karl Swedberg <[EMAIL PROTECTED]> wrote:
>
> > > And that's why Ariel is da man! Nice one.
>
> > > --Karl
> > > ____________
> > > Karl Swedbergwww.englishrules.comwww.learningjquery.com
>
> > > On Jun 12, 2008, at 7:09 AM, Ariel Flesler wrote:
>
> > > > Ooooooor....
>
> > > > var fileName = $('img').attr('src').split('/').pop();
>
> > > > Cheers :)
>
> > > > --
> > > > Ariel Flesler
> > > >http://flesler.blogspot.com/
>
> > > > On 11 jun, 22:29, Karl Swedberg <[EMAIL PROTECTED]> wrote:
> > > >> Hi there,
>
> > > >> You could do it like this:
>
> > > >> var path = $('img').attr('src');
> > > >> var fileName = path.slice(path.lastIndexOf('/')+1);
>
> > > >> --Karl
> > > >> ____________
> > > >> Karl Swedbergwww.englishrules.comwww.learningjquery.com
>
> > > >> On Jun 11, 2008, at 7:36 PM, yo2lux wrote:
>
> > > >>> path variable store the following: /themes/mytheme/images/logo.gif:
>
> > > >>> var path = $('img').attr('src');
>
> > > >>> is possible to obtain the image name without path ? I need logo.gif
> > > >>> I need a Javascript or jQuery function to solve this?
>
> > > >>> Thanks!- Ocultar texto de la cita -
>
> > > >> - Mostrar texto de la cita -
