Thanks guys much appreciated.
I tried the last one :
$('.equipment a.i-right1').filter(function(i) {
return ( i > 0 && i < 9 );
}).hide();
And it worked.
For say
$('.equipment a.i-right1')
$('.equipment a.i-right2')
$('.equipment a.i-right5')
$('.equipment a.i-rightx')
How would i put that into a loop?
Thanks.
On Jul 8, 10:16 pm, "Jonathan Sharp" <[EMAIL PROTECTED]> wrote:
> Hi Johnee,
>
> Another approach would be:
>
> $('.equipment a.i-right1').each(function(i) {
> if ( i > 0 && i < 9 ) {
> $(this).hide();
> }
>
> });
>
> or this would work too:
>
> $('.equipment a.i-right1').filter(function(i) {
> return ( i > 0 && i < 9 );
>
> }).hide();
>
> Cheers,
> -Jonathan
>
> On Tue, Jul 8, 2008 at 12:00 PM, JohneeM <[EMAIL PROTECTED]> wrote:
>
> > Hi guys how can i run this in a single statement without manually
> > putting in the numbers?
>
> > $('.equipment a.i-right1:eq(1)').hide();
> > $('.equipment a.i-right1:eq(2)').hide();
> > $('.equipment a.i-right1:eq(3)').hide();
> > $('.equipment a.i-right1:eq(4)').hide();
> > $('.equipment a.i-right1:eq(5)').hide();
> > $('.equipment a.i-right1:eq(6)').hide();
> > $('.equipment a.i-right1:eq(7)').hide();
> > $('.equipment a.i-right1:eq(8)').hide();
>
> > Note that im skipping the first array [0] due to wanting it to show.
>
> > Also this one :
>
> > $('.performance-parts #content-container
> > a.lightbox:eq(8)').lightBox();
> > $('.performance-parts #content-container
> > a.lightbox:eq(9)').lightBox();
>
> > They need to be in their own array as i want to run a seperate
> > lightbox for each image, is this possible?
>
> > Thanks.
