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[jQuery] Re: A better way to do this?
MorningZ
Sun, 24 Aug 2008 22:48:02 -0700
".find()" should help $(this).find("ul > li > a").each(
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[jQuery] A better way to do this?
Dana
[jQuery] Re: A better way to do this?
MorningZ
[jQuery] Re: A better way to do this?
Dana
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