a common trick i use to get around situations where an event may be
bound twice is to add an unbind into the chain. like so:
var kd = function(event) {
alert(event.keyCode);
}
$().unbind('keydown', kd).keydown(kd);
it's a bit quick and dirty, but it works.
-micah
On Aug 29, 9:12 am, me-and-jQuery <[EMAIL PROTECTED]> wrote:
> Hello. So I have a problem that when I get jQuery code in ajax
> response and you click few times to activate ajax call, there are
> multiple instances of same code. Lets see the example with keydown.
>
> FILE 1:
> <script>
> $(document).ready(
> function() {
> $("#my_div").click(function() {
> $.ajax({
> type: "GET",
> url: "test.php",
> success:
> function(data) {
>
> $("#div_ajax").html(data);
> }
> })
> })
> }
> )
> </script>
> <div id="my_div">Click here</div>
> <div id="div_ajax"></div>
>
> FILE 2 - AJAX RESPONSE:
> <script>
> $().keydown(function(event) {
> alert(event.keyCode);});
>
> </script>
> Ajax content loaded...
>
> So, if I click on my_div twice, there will be two listeners for keys
> and for same keydown two alerts.
>
> I can solve this issue with ifs, but what is the best way to prevent
> this behaviour? Maybe in the way of singletons or something?
>
> Thanks for any advice, I am sure there must be simple and effective
> solution. Have a nice day.
