Two questions?
Wouldn't I have to still pass a value for i for each instantiation of
an li? Or do I not quite understand how this works? Basically could
you explain how this works a little bit so that I fully understand the
jQuery and JS behind it. I would really appreciate that.
The other question is pretty close to the first question. For
implementing this, I know I would most likely have to put this code
after the superfish call in the document.ready part of the code? I
believe I understand that the first post would be called with each li
but it looks like it would be looking at the parent item instead of
the brother items.
I guess both questions really just fall to a little bit more
explanation of how these functions would work, but thanks Ricardo! I
have a couple other tasks to tackle right now but I will probably be
able to give this a shot tomorrow and give more feedback then.
~Aaron
On Sep 23, 2:09 pm, ricardobeat <[EMAIL PROTECTED]> wrote:
> or better yet (thanks Eric!):
>
> $('#menu li').each(function(i){
> $(this).css('z-index',10-i);
>
> });
>
> - ricardo
>
> On Sep 23, 3:06 pm, ricardobeat <[EMAIL PROTECTED]> wrote:
>
> > $('#menu li').each(function(){
> > var zindex = 10 - $(this).parent().find('li').index(this);
> > $(this).css('z-index',zindex);
>
> > });
>
> > On Sep 23, 10:12 am, Aaron <[EMAIL PROTECTED]> wrote:
>
> > > Unfortunately I don't understand the jQuery enough to put something
> > > like that together. Anyone else understand it enough to give this a
> > > whirl?
>
> > > Aaron
>
> > > On Sep 22, 9:55 pm, "Joel Birch" <[EMAIL PROTECTED]> wrote:
>
> > > > Your solution for fixing this incarnation of the IE z-index bug is
> > > > actually the only one I have ever come across, so whilst it is hacky,
> > > > it's probably as good as you are going to get. I guess a nifty bit of
> > > > jQuery could make applying the z-indexes easier and keep the source
> > > > HTML clean. If anyone wants to give that a go please share the
> > > > results!
>
> > > > Joel Birch.
