Why do you need to test the existence of the parent container?
The HTML you listed was:
<div id="parentContianer">
<div id="#childEle1"></div>
<div id="#childEle2"></div>
<div id="#childEle3"></div>
<div id="#childEle4"></div>
<div id="#childEle5"></div>
<div id="#childEle6"></div>
</div>
If your code runs any time after block of HTML e.g. in a "ready" function or
even in inline code after the HTML, both the parentContianer [sic] and all
of its child elements have already been created. Just grab your references
and run.
-Mike
> From: Micky Hulse
>
> Hmmm, also, I suppose I could do the below when setting-up my
> variables:
>
> var $parentObj = $('#parentContianer');
> if($parentObj.length > 0) {
> // $parentObj exists, cache child objects:
> var $childObj1 = $('#childEle1');
> var $childObj2 = $('#childEle2');
> var $childObj3 = $('#childEle3');
> var $childObj4 = $('#childEle4');
> var $childObj5 = $('#childEle5');
> var $childObj6 = $('#childEle6');
> }
>
> Is that an acceptable or weird way to do it?
