Following your logic, an L4 element will never be a direct child of an
L1, so that would always return 0. Also you don't need two objects to
do what you were trying at first, you can do $('some > thing',
'#inhere')
Let me see if I understand you. Given the following mark-up:
<body>
<div class="L1">
<p>
<span class="L3">
<a class="L4" />
</span>
</p>
</div>
<div class="L1 thisOne">
<p>
<span class="L3 other">
<a class="L4" />
</span>
</p>
</div>
</body>
You want to find only the <a> (4) elements that are children of <div>
(1) AND children of <span>(3). Right. L4 is not a direct children of
L1 so you need another approach.
$('span.other a').filter(function(){ return !!$
(this).parents('div').length })
which equates to
$('L3.other L4').filter(function(){ return !!$
(this).parents('L1').length })
or, if what you want is the opposite, to find <a>'s in <span> that are
also a child of <div>
$('span a').filter(function(){ return !!$
(this).parents('div.thisOne').length })
which equates to
$('L3 > L4').filter(function(){ return !!$
(this).parents('L1').length }) // returns true if the element is a
child of L1
There are many ways of simplifying that based on your element classes
or attributes, but that's all I could come up with without seeing your
HTML.
cheers,
- ricardo
On Oct 22, 6:16 pm, Dan Finch <[EMAIL PROTECTED]> wrote:
> You're right, I do that all the time :). I'm getting my side effects
> mixed up. What I can't actually do is match against ancestors of the
> context. For example, $( ".L1>.L4", $( ".L3" ) ), where the n
> represents the level of DOM depth.
>
> On Oct 22, 2:38 pm, MorningZ <[EMAIL PROTECTED]> wrote:
>
> > Have you tried those?
>
> > There's no reason why
>
> > $( "p>a", $( "div" ) );
>
> > wouldn't find all <a> that are direct descendants of <p> tags inside
> > <div> tags
>
> > On Oct 22, 2:43 pm, Dan Finch <[EMAIL PROTECTED]> wrote:
>
> > > If there's a way, what would it take to be able to use complex
> > > selectors (those with " ", "~", ">", etc.) with filtering functions.
> > > For example,
>
> > > $( "div" ).find( "p>a" );
> > > $( "p>a", $( "div" ) );
>
> > > Thanks- Hide quoted text -
>
> > - Show quoted text -
