If you are indeed returning an array from PHP, then the received JSON should be a js array. Got this online ?
-- Ariel Flesler http://flesler.blogspot.com/ On Oct 25, 6:26 pm, jfrymann <[EMAIL PROTECTED]> wrote: > Hi, > I have just started using jQuery and am trying to get data back from > a mysql database in json format. I am using PHP to query the database > and returning it with the json_encode method. (Basically I am > following the example in the documentation > -http://docs.jquery.com/Ajax/jQuery.post#urldatacallbacktype) > > The problem I am having is that the example only returns one json > object rather than an array of them and I'm not sure how to modify the > calls to either the php encode json or how to access the data when it > is returned through jquery. > > At the moment my php looks like this: > > while($row = mysql_fetch_array($result)) > { > echo json_encode(array("file"=>$row['name'],"byline"=> > $row['byline'])); > > } > > and the jQuery: > > $.post("getimages.php", { location: opt_choice, curr_img: img_cnt, > limit: img_lim }, > function(data){ > alert(data); > }, "json"); > > How can I set it up to access multiple objects? > Thanks for the help!
