in http://www.finaleshop.com/includes/javascript/rahnema1.js
you have a typo
var flag=false;
//$().ready(function(){
> $(function() {
that ">" sign is problematic.
continuing reading...
On Wed, Dec 10, 2008 at 10:40 AM, [EMAIL PROTECTED]
<[EMAIL PROTECTED]> wrote:
>
> (thanks for your answers :*)
>
> <script type="text/javascript" src="includes/javascript/jqCore.js"></
> script>
> <script type="text/javascript" src="includes/javascript/rahnema1.js"></
> script>
>
> the urls are :
> http://www.finaleshop.com/includes/javascript/rahnema1.js
> http://www.finaleshop.com/includes/javascript/jqCore.js
>
> On Dec 10, 12:38 pm, "Alexandre Plennevaux" <[EMAIL PROTECTED]>
> wrote:
>> can you cut and paste the full html on the page, and show the
>> javascript external file links. that should be enoughf thanks.
>>
>> On Wed, Dec 10, 2008 at 10:36 AM, [EMAIL PROTECTED]
>>
>> <[EMAIL PROTECTED]> wrote:
>>
>> > ok, the code is:
>>
>> > var flag=false;
>> > $().ready(function(){
>>
>> > $("div#peik").hide();
>> > $('div#cardbanki > div').hide();
>> > $('div#pardakht > div').hide();
>>
>> > ...
>>
>> > the error is on first div (like i said in first post)
>> > and if you want url , i must say that it's a persian eshop site
>> >http://www.finaleshop.com
>> > you must buy a product and then goto checkout_confirmation.php page
>> > (i suggest that pm me to talk about it ! :-s )
>>
>> > On Dec 10, 12:33 pm, "[EMAIL PROTECTED]" <[EMAIL PROTECTED]>
>> > wrote:
>> >> nooo,
>> >> it wasn't helpful
>>
>> >> if anybody can help me please send a pm me at yahoo messsenger at
>> >> ( [EMAIL PROTECTED])
>> >> thankks :-s
>>
>> >> On Dec 10, 12:22 pm, JQueryProgrammer <[EMAIL PROTECTED]> wrote:
>>
>> >> > Try this:
>>
>> >> > $(function() {
>> >> > // your code goes here.
>>
>> >> > });
>>
>> >> > Also while including the jquery file, write it as:
>>
>> >> > <script type="text/javascript" src="jquery.js"></script>
>>
>> >> > Check whether this helps.
>>
>> >> > On Dec 10, 2:17 pm, "[EMAIL PROTECTED]" <[EMAIL PROTECTED]> wrote:
>>
>> >> > > hi
>>
>> >> > > i have written jquery for a site;
>> >> > > after a while for sth that i don't know it don't work anymore
>> >> > > and direbug give an error like this:
>>
>> >> > > $("div#peik") is null
>> >> > > $("div#peik").hide();
>>
>> >> > > and when i try to write
>>
>> >> > > $(document).ready()
>>
>> >> > > in firebug, it return :
>>
>> >> > > TypeError: $(document) is null
>>
>> >> > > whyyy is that?
>> >> > > pleeeas answer as soon as posible
>> >> > > thanks
