in http://www.finaleshop.com/includes/javascript/rahnema1.js
you have a typo var flag=false; //$().ready(function(){ > $(function() { that ">" sign is problematic. continuing reading... On Wed, Dec 10, 2008 at 10:40 AM, [EMAIL PROTECTED] <[EMAIL PROTECTED]> wrote: > > (thanks for your answers :*) > > <script type="text/javascript" src="includes/javascript/jqCore.js"></ > script> > <script type="text/javascript" src="includes/javascript/rahnema1.js"></ > script> > > the urls are : > http://www.finaleshop.com/includes/javascript/rahnema1.js > http://www.finaleshop.com/includes/javascript/jqCore.js > > On Dec 10, 12:38 pm, "Alexandre Plennevaux" <[EMAIL PROTECTED]> > wrote: >> can you cut and paste the full html on the page, and show the >> javascript external file links. that should be enoughf thanks. >> >> On Wed, Dec 10, 2008 at 10:36 AM, [EMAIL PROTECTED] >> >> <[EMAIL PROTECTED]> wrote: >> >> > ok, the code is: >> >> > var flag=false; >> > $().ready(function(){ >> >> > $("div#peik").hide(); >> > $('div#cardbanki > div').hide(); >> > $('div#pardakht > div').hide(); >> >> > ... >> >> > the error is on first div (like i said in first post) >> > and if you want url , i must say that it's a persian eshop site >> >http://www.finaleshop.com >> > you must buy a product and then goto checkout_confirmation.php page >> > (i suggest that pm me to talk about it ! :-s ) >> >> > On Dec 10, 12:33 pm, "[EMAIL PROTECTED]" <[EMAIL PROTECTED]> >> > wrote: >> >> nooo, >> >> it wasn't helpful >> >> >> if anybody can help me please send a pm me at yahoo messsenger at >> >> ( [EMAIL PROTECTED]) >> >> thankks :-s >> >> >> On Dec 10, 12:22 pm, JQueryProgrammer <[EMAIL PROTECTED]> wrote: >> >> >> > Try this: >> >> >> > $(function() { >> >> > // your code goes here. >> >> >> > }); >> >> >> > Also while including the jquery file, write it as: >> >> >> > <script type="text/javascript" src="jquery.js"></script> >> >> >> > Check whether this helps. >> >> >> > On Dec 10, 2:17 pm, "[EMAIL PROTECTED]" <[EMAIL PROTECTED]> wrote: >> >> >> > > hi >> >> >> > > i have written jquery for a site; >> >> > > after a while for sth that i don't know it don't work anymore >> >> > > and direbug give an error like this: >> >> >> > > $("div#peik") is null >> >> > > $("div#peik").hide(); >> >> >> > > and when i try to write >> >> >> > > $(document).ready() >> >> >> > > in firebug, it return : >> >> >> > > TypeError: $(document) is null >> >> >> > > whyyy is that? >> >> > > pleeeas answer as soon as posible >> >> > > thanks