Thanks Mike,
I'm following this tutorial here:
http://www.learningjquery.com/2007/10/a-plugin-development-pattern
I have several public functions like this:
$.fn.response.redirect.default = function (){//something here};
$.fn.response.redirect.type1 = function (){//something here};
$.fn.response.redirect.type2 = function (){//something here};
I wanted to be able to call the appropriate function depending on a
string passed back to me via json
Im thinking of doing it like this (based on your example):
if($.fn.response.redirect[response.redirect_type] !== undefined)
$.fn.response.redirect[response.redirect_type]();
else
$.fn.response.redirect.default();
Do you think it would work?
Thanks again for your help
Raine
On Jan 2, 3:34 am, "Michael Geary" <m...@mg.to> wrote:
> I don't know about the $.fn.myplugin part - that's not how you would
> typically call a plugin function in the first place.
>
> But in general, given any object 'foo' and any property 'bar', you can
> reference the 'bar' property in either of two ways:
>
> foo.bar
>
> Or:
>
> foo['bar']
>
> If 'bar' is a method, you can call it with:
>
> foo.bar(...);
>
> Or:
>
> foo['bar'](...);
>
> Either one means exactly the same thing.
>
> One common use for this is with show and hide methods. Instead of coding:
>
> if( doShow )
> $('#foo').show();
> else
> $('#foo').hide();
>
> You can code:
>
> $('#foo')[ doShow ? 'show' : 'hide' ]();
>
> -Mike
>
> > From:yellow1912
>
> > Something like this
> > var func = 'myFunc';
>
> > Can I call the function like this for example:
>
> > $.fn.myplugin.(func)();
>
> > (I'm using this in a plugin I'm working on)
>
> > Thank you very much
