Thanks Ricardo. Excellent, that did the trick.
Can I ask you one more thing?
1. Before I put all the code into a plugin, I used to have it like
this:
$("#checkoutForm form").livequery(function() {
$(this).ajaxForm(options);
});
2. Now with the plugin I bind it this way:
$("#checkoutForm).myplugin();
And inside the plugin I triedL
$this.find('form').livequery(function() {
$(this).ajaxForm(options);
});
3. This doesn't seem to have the same effect as expected. I'm pretty
sure I missed something, I just cant find out
Regards
Raine
Inside the plugin I try this:
$this = this;
$this.livequery(function() {
$this.ajaxForm(options);
});
On Jan 6, 10:08 am, Ricardo Tomasi <ricardob...@gmail.com> wrote:
> Not sure that this is it, but
>
> $.fn.myplugin = function(options) {
> return this.find('form').ajaxForm();
>
> });
>
> ?
>
> On Jan 6, 1:59 pm, yellow1912 <yellow1...@gmail.com> wrote:
>
> > Hi all, I have a question regarding jquery object:
>
> > if I bind my plugin like this:
>
> > $('#myButton').myplugin();
>
> > And inside my plugin, I want to bind ajaxForm listener to all forms
> > inside 'this' current element, what is the best way to do it? I can
> > get the id by using $this.attr('id'), but there is no guarantee that
> > the users will always pass in an id.
>
> > (function($) {
> > //
> > // plugin definition
> > //
>
> > $.fn.myplugin = function(options) {
> > // bind ajax form to 'this'
>
> > }});
>
> > Thank you for your help and suggestions
>
> > Raine
