Here's the function I use to rotate the menu: http://paste.pocoo.org/show/99509/ The icons are located inside divs with ids 'pos_1' through 'pos_5', 'pos_1' being the leftmost icon, and 'pos_5' being the rightmost icon. The all have class 'pos'.
The problematic case occurs when the user clicks on 'pos_1' or 'pos_5' and the menu has to be rotated by 2 steps. rotate() is then called twice, and so the call to .animate() is executed twice for each div. I can't use a single call to .animate() because then the divs would jump directly to their final destination instead of passing through adjacent positions. I've tried the following alternatives: 1) Using queue: false and using the second call with setTimeout so that it is executed just before the first animation completes. 2) Using queue: true as in original code but calling .stop() a fraction of a second before the first animation completes on its own so that it is interrupted and the second animation in the queue starts immediately. 3) Putting the second call to .animate() in the callback function of the first animate. All of these alternatives produced exactly the same results as the original code. The rotating menu makes a noticeable pause after the first animation before proceeding with the second. On Tue, Jan 13, 2009 at 8:20 PM, Nikola <nik.cod...@gmail.com> wrote: > > It's hard to tell without having a look at the code. You may want to > try http://paste.pocoo.org to post code like this. > > Are you chaining the animations? ie. $(this).animate({},speed).animate > ({},speed).animate({},speed); > > You could always try setting a delay on your second animation with > setTimeout. > > setTimeout ('$(this).animate({},speed)', 400); > > Hope that helps. > Nikola
