You'll need to save the output into a variable, then loop through that
to create new options and replace the existing ones.
var new_opts = $.makeArray($('#ops-memb option')).sort(...
There's probably a neat jQuery way to do all of this compactly.
On Fri, Jan 16, 2009 at 1:44 PM, mtz <tracey.zellm...@gmail.com> wrote:
>
> Thanks.
> I can make the array now and it legitimately sorts.
> However, I can't see an easy way to get the values in the array back
> into the <option id='123''>A name</option>
> format again, so I can put teh HTML into the select .
>
> On Jan 16, 1:33 pm, brian <bally.z...@gmail.com> wrote:
>> http://docs.jquery.com/Utilities/jQuery.makeArray#obj
>> -- snip --
>> jQuery.makeArray( obj )
>> Turns anything into a true array.
>> -- snip --
>>
>> On Fri, Jan 16, 2009 at 1:25 PM, Kean <shenan...@gmail.com> wrote:
>>
>> > Only true arrays will inherit the sort method.
>>
>> > On Jan 16, 10:10 am, brian <bally.z...@gmail.com> wrote:
>> >> Maybe use makeArray() first. Something like:
>>
>> >> $.makeArray($('#ops-memb option')).sort(...
>>
>> >> On Fri, Jan 16, 2009 at 11:04 AM, mtz <tracey.zellm...@gmail.com> wrote:
>>
>> >> > I have a select list into which I place new option elements, and I
>> >> > want to show them in sorted order. I've searched around and tried some
>> >> > approaches, but not successful yet.
>>
>> >> > Here is an example.
>> >> > It may not be the best use of jQuery, but at least I understand it.
>> >> > The select element has id ops-memb
>> >> > I get the current content, then add another option item.
>>
>> >> > var members = $('#ops-memb').html() + "<option id='507'>Another Item</
>> >> > option>";
>> >> > $'#ops-memb').html(members);
>>
>> >> > This works.
>> >> > Now I try to sort
>>
>> >> > $('#ops-memb option').sort(function(a,b) {
>> >> > return $(a).text() > $(b).text() ? 1 : -1;
>> >> > });
>>
>> >> > I get an error message that $('#ops-memb').sort is not a function
>>
>> >> > Could someone help me understand what I am doing wrong and how to get
>> >> > this to work correctly?
>>
>> >> > Thanks.
