Does it work, to write all checked id's into a hidden field? Which
then gets submitted?
On 30 Jan., 16:27, heohni <heidi.anselstet...@consultingteam.de>
wrote:
> Hi,
>
> I am using this:
>
> <input type="checkbox" name="paradigm" value="{$value.ver_id}" />
>
> $(document).ready(function(){
> $("#paradigm_all").click(function(){
> var
> checked_status=this.checked;$("inp...@name=paradigm]").each
> (function(){
> this.checked=checked_status;
> });
> });
>
> });
>
> to check and uncheck a list of articles.
> Now I want to sumbit the checked articles, but I don't know how to do
> that.
>
> I can't use <input type="checkbox" name="paradigm[]"
> value="{$value.ver_id}" />
> as then the jquery doesn#t work anymore.
>
> But how can I transfer all checked Id's to the next page?
> Any help?
>
> Thanks a bunch!
