How about, instead of:
x = this.id;
try:
x = $(this).attr('id');
On Feb 6, 1:22 am, Mario Moura <moura.ma...@gmail.com> wrote:
> Hi Folks
>
> I did this with ajax tab options and Jquery Form
>
> $(document).ready(function() {
> $("#myForm").ajaxForm( function() {
> $("#tabs").tabs("select",2);
> });
>
> });
>
> Inside of my tab 1 have
>
> <input type="submit" id="back" class="click" value="« Back" name="back"/>
>
> <input type="submit" id="continue" class="click" value="Continue »"
> name="continue"/>
>
> As you can see if I submit #myForm I will go to next tab
> $("#tabs").tabs("select",2);
>
> But to back I am having problems. Because is a second submit button. So I am
> trying this:
>
> $(document).ready(function() {
>
> $(".click").click(function(){
> //Get the id of this clicked item
> x = this.id;
>
> });
>
> // before submit, call BackOrContinue
> var options = {
> beforeSubmit: BackOrContinue
> };
>
> $("#myform").ajaxForm(options);
>
> function BackOrContinue {
>
> if (x == "back") {
> $("#tabs").tabs("select",0);
> } else {
> $("#tabs").tabs("select",2);
> }
> }
>
> });
>
> My error is $ is not defined
>
> I tried
>
> $("#myForm").ajaxForm( function() {
> x = this.id;
> alert(x);
> if (x == "back") {
> $("#tabs").tabs("select",0);
> } else {
> $("#tabs").tabs("select",2);
> }
> });
>
> and x = "undefined"
>
> What is missing?
>
> Regards
>
> macm
