On Sun, Mar 1, 2009 at 9:59 PM, Wil Everts <wileve...@gmail.com> wrote:
> > One of my favorite examples of this is the Flickr example on Visual > jQuery (http://remysharp.com/visual-jquery/). > > $.getJSON(" > http://api.flickr.com/services/feeds/photos_public.gne?tags=cat&tagmode=any&format=json&jsoncallback= > ?", > function(data){ > $.each(data.items, function(i,item){ > $("<img/>").attr("src", item.media.m).appendTo("#images"); > if ( i == 3 ) return false; > }); > }); > }); > > Here you can see that each presents you with a new object (called > item) and it's index (i) each time through the loop below for all the > returned matches for data.items. In your example (without seeing your > json) item.id should work fine without an index. > Hi Wil, so if i understood well, having the following JSON: > {"records":[{"id":1,"abbreviation":"fre","description":"french"},{"id":2,"abbreviation":"eng","description" > :"english"},{"id":3,"abbreviation":"ger","description":"german"},{"id":4,"abbreviation":"svk","description" > :"slovak"},{"id":5,"abbreviation":"spa","description":"spanish"},{"id":6,"abbreviation":"usa","description" > :"american"},{"id":7,"abbreviation":"ita","description":"italian"},{"id":8,"abbreviation":"por","description" > :"portuguese"},{"id":9,"abbreviation":"cze","description":"czech"},{"id":10,"abbreviation":"rus","description" > :"russian"},null,null,null]} > > i should write : $.each(data.records, function(i,item){...}); where "data.records" is the name of my JSON result...so records (in my JSON). am I right ? A>
