[jQuery] Re: Array function

[Jonathan Vanherpe (T & T NV)]

Alex Wibowo wrote:

Gday,


Is there a short way to do:

   $("#idOne").show();
   $("#idTwo").show();
    ?



So far, my best bet is to do:

    $.each(["#idOne","#idTwo"],function(){
                    $(""+this).show();
   });


Thanks in advance!

$('#idOne, #idTwo').show();
just like css

Jonathan

--
Jonathan Vanherpe - Tallieu & Tallieu NV - jonat...@tnt.be