function buildMenu(myMenu)
{
     var i, menuItems = '';
     var $menu = $('<div class="MainMenuItems" />');
     for (i in menu1)
     {
          menuItems += menu1[i];
     }
     var menuHTML = $menu.append(menuItems);
     $(myMenu).html(menuHTML);
}

buildMenus('.MainMenu');

It's untested, but does something like this work for you?
What does your 'menu1' variable look like? I'm assuming its an array
of HTML string sets, like '<div>menu1</div>', '<div>menu2</div>'


On Apr 8, 9:15 am, "jomowe...@gmail.com" <jomowe...@gmail.com> wrote:
> Not sure the best way to do this, but I am trying to build a menu with
> a function then to insert it into the dom with jquery.  I have tried
> bothe the methods below to no avail.  All I am getting is "undefined"
> where the new links should be. If anyone can tell me what I am doing
> wrong, or give a little hint on a better way to code this, you would
> save the day
>
> //The menu function
> function buildMenu()
> {
>    var i;
>       for (i in menu1)
>       {
>            var menuItem = menu1[i];
>            document.write(menuItem);
>         }
>
> }
>
> // The jquery manipulation Attempt #1
> $(".MainMenu").html("<div class='MainMenuItems'>" + buildMenu() + "</
> div>");
>
> // Attempt #2
> $(".MainMenu").html("<div class='MainMenuItems'><script>buildMenu();</
> script></div>");

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