Hi Liming,
Just a child combinator rather than a descendant combinator:
$("div[id ^= 'childtest_' ] > :first-child").each(function() {
alert( $(this).attr("id") )
});
--Karl
____________
Karl Swedberg
www.englishrules.com
www.learningjquery.com
On Apr 29, 2009, at 4:14 PM, Liming wrote:
my bad. I was changing it around. It shoudl be
$("div[id ^= 'childtest_' ] :first-child").each(function() {
alert( $(this).attr("id") )
});
On Apr 29, 3:55 pm, MorningZ <morni...@gmail.com> wrote:
I don't understand.. there's no where that you are using ":first-
child" like your subject line says
On Apr 29, 11:43 am, Liming <lmxudot...@gmail.com> wrote:
Hello all, I have a lay out like so
<div id="childtest_toprow">
<div id="subtest_1">
<div id="subtest_1_1"></div>
<div id="subtest_1_2"></div>
</div>
</div>
<div id="subtest_2">
</div>
</div>
I want to select the first child of "childtest_toprow" which is
"subtest_1"
when i do
$("div[id ^= 'childtest_' ] :nth-child(1)").each(function() {
alert( $(this).attr("id") )
});
I get "subtest_1" AND "subest_1_1"
what am I doing wrong?
Thanks
ps: i'm using firefox 3 and IE 7
