Nope. This: var $thisCell, $tgt = $(event.target); does not mean: var $thisCell = $(event.target); var $tgt = $(event.target); After all, there's only one jQuery object being created in the first example, and two distinct objects in the second. Nor does it set both variables to the same object, like this code: var $thisCell, $tgt; $thisCell = $tgt = $(event.target);
What it really means is: var $thisCell; var $tgt = $(event.target); -Mike _____ From: Richard D. Worth Yup. See https://developer.mozilla.org/En/Core_JavaScript_1.5_Reference/Statements/Va r - Richard On Thu, May 14, 2009 at 2:12 AM, runrunforest <craigco...@gmail.com> wrote: Hi, I see this line in a plugin var $thisCell, $tgt = $(event.target); does that mean: var $thisCell = $(event.target); var $tgt = $(event.target);