Hi problem fixed,

The problem is the white space ,

I removed the white space got output ,

Thanks for you interest

Bye

On Wed, Jun 3, 2009 at 5:35 PM, ryan.j <ryan.joyce...@googlemail.com> wrote:

>
> what is the response header's Content-Type?
>
> On Jun 3, 12:33 pm, bharani kumar <bharanikumariyer...@gmail.com>
> wrote:
> > Hi See ,
> >
> > i tried like
> >
> > emailInfo.html(data);
> >
> > It print fine ,
> >
> > When i out into condition, there i facing Problem ,
> >
> > like
> > for example
> >
> > var test = emailInfo.html(data);
> >
> > if(test == 'ACCT'){
> >
> > emailInfo.html(test);
> >
> > }else{
> >
> > emailInfo.html("Somthing bla lbla ");
> >
> >
> >
> > }
> > On Wed, Jun 3, 2009 at 4:54 PM, ryan.j <ryan.joyce...@googlemail.com>
> wrote:
> >
> > > it's not working because the value of data isn't "ACCT" or "ACAT".
> >
> > > is the response actually returning anything to data? add ...
> >
> > > alert( "data = " + data);
> >
> > > to your success case.
> >
> > > On Jun 3, 12:03 pm, bharani kumar <bharanikumariyer...@gmail.com>
> > > wrote:
> > > >   $(document).ready(function(){
> > > >     $("#txt_airport_code").keyup(function () {
> > > >         //var getValue = $("#txtUser").attr("value");
> >
> > > >         var emailInfo = $("#msg1");
> > > >         var airport_code = "airport_code";
> > > >         $.ajax({
> > > >             type: "POST",
> > > >             data:
> > > > "str="+$("#txt_airport_code").attr("value")+"&code="+airport_code,
> > > >             url: "check.php",
> > > >             beforeSend: function(){
> > > >                 emailInfo.html("Checking Email...");
> > > >             },
> > > >             success: function(data){
> > > >                 if(data == "ACAT"){
> > > >                     emailInfo.html("ACAT Already Exist");
> > > >                 }else if(data == "ACCT"){
> > > >                     emailInfo.html("ACCT Already Exist");
> >
> > > >                 }else{
> > > >                     emailInfo.html("Available");
> > > >                 }
> > > >             }
> > > >         });
> > > >     });
> > > >   });
> >
> > > > Hi All ,
> >
> > > > This my snippet ,
> >
> > > > am doing the already exist functionality ,
> >
> > > > The above snippet is working fine ,
> >
> > > > but the problem is ,,
> >
> > > > Always the condition  goes to the Available , am not able to mark out
> my
> > > > Error spot,
> >
> > > > Can u tell me , where i made the mistake ,
> >
> > > > Thanks advance
> >
> > --
> > Regards
> > B.S.Bharanikumarhttp://php-mysql-jquery.blogspot.com/
>



-- 
Regards
B.S.Bharanikumar
http://php-mysql-jquery.blogspot.com/

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