$.ajax should be used instead of $.post.
WD
On May 27, 5:48 pm, mrozko <jakubik.mar...@gmail.com> wrote:
> Hi All,
>
> I am looking for the solution of this problem:
>
> i have a login form. i would like to "shake" the login-form box, if
> the authentication (PHP+MySQL) failed.
> i use jQuery.post for posting the values from login form to the PHP-
> script (used for validation - named "backend.php").
>
> This is the code:
>
> <script type="text/javascript">
>
> $(document).ready(function() {
> $("#submit_butt").click( function() {
> // configurations for the buzzing effect. Be careful not to
> make it
> too annoying!
> var conf = {
> frequency: 5000,
> spread: 5,
> duration: 600
> };
> /* do your AJAX call and processing here...
> .... */
> var unameval = $("#username").val();
> var pwdval = $("#pwd").val();
>
> $.post("backend.php", { username: unameval, pwd: pwdval },
> function(data){
> if(data.length >0) {
>
> window.location.href("account.php");
>
> }
> });
> // this is the call we make when the AJAX callback function
> indicates a login failure
> $("#login").vibrate(conf);
> // let's also display a notification
> if($("#errormsg").text() == "")
> $("#loginform").append('<p id="errormsg">Nesprávne
> meno alebo heslo!
> </p>');
> // clear the fields to discourage brute forcing :)
> $("#username").val("");
> $("#pwd").val("");
> });
>
> });
>
> </script>
>
> Could you pls help me? Any suggestions?
>
> Thanks a lot.
>
> Best,
> Marian
